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Consider the following CFL
L1 = {an|n≥1}
L2 = {bnan|n≥1}
L3 = {0n1m |n = 2m, n,m ≥ 0}
L4 = {ap|p is odd number}
How many statements are true?
(i) Complement of L1 is also regular.
(ii) Union of L2 and L3 is also CFL
(iii) Intersect of L1 and L4 is also CFL
(iv) Concatenation of L1 and L2 is also CFL
    Correct answer is '4'. Can you explain this answer?
    Most Upvoted Answer
    Consider the following CFLL1 = {an|n≥1}L2 = {bnan|n≥1}L3 = {0n1m...
    Concept:
    The given grammar is,
    L1 = {an|n ≥ 1} 
    It regular grammar, 


    L2 = {bnan|n ≥ 1}
    It is not regular but DCFL because we need to compare a number of b's with the number of a's so we need one stack for comparisons.
    L3 = {0n1m |n = 2m, n,m ≥ 0}
    It is not regular but DCFL because we need to compare a number of b's with the number of a's so we need one stack for comparisons.
    L4 = {ap|p is odd number}
    It regular grammar,

    (i) Complement of L1 is also regular.
    True, L1 is regular so complement is also regular and every regular is context-free so it is true.
    (ii) Union of L2 and L3 is also CFL
    True, the Union of two CFLs is also CFL by closure property.
    (iii) Intersect of L1 and L4 is also CFL
    True, L1 and L4 both are regular and the intersection of regular is also regular and every regular is CFL.
    (iv) Concatenation of L1 and L2 is also CFL.
    True, the Concatenation of two CFLs is always CFL.
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    Consider the following CFLL1 = {an|n≥1}L2 = {bnan|n≥1}L3 = {0n1m |n = 2m, n,m ≥ 0}L4 = {ap|p is odd number}How many statements are true?(i) Complement of L1 is also regular.(ii) Union of L2 and L3 is also CFL(iii) Intersect of L1 and L4 is also CFL(iv) Concatenation of L1 and L2 is also CFLCorrect answer is '4'. Can you explain this answer?
    Question Description
    Consider the following CFLL1 = {an|n≥1}L2 = {bnan|n≥1}L3 = {0n1m |n = 2m, n,m ≥ 0}L4 = {ap|p is odd number}How many statements are true?(i) Complement of L1 is also regular.(ii) Union of L2 and L3 is also CFL(iii) Intersect of L1 and L4 is also CFL(iv) Concatenation of L1 and L2 is also CFLCorrect answer is '4'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Consider the following CFLL1 = {an|n≥1}L2 = {bnan|n≥1}L3 = {0n1m |n = 2m, n,m ≥ 0}L4 = {ap|p is odd number}How many statements are true?(i) Complement of L1 is also regular.(ii) Union of L2 and L3 is also CFL(iii) Intersect of L1 and L4 is also CFL(iv) Concatenation of L1 and L2 is also CFLCorrect answer is '4'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the following CFLL1 = {an|n≥1}L2 = {bnan|n≥1}L3 = {0n1m |n = 2m, n,m ≥ 0}L4 = {ap|p is odd number}How many statements are true?(i) Complement of L1 is also regular.(ii) Union of L2 and L3 is also CFL(iii) Intersect of L1 and L4 is also CFL(iv) Concatenation of L1 and L2 is also CFLCorrect answer is '4'. Can you explain this answer?.
    Solutions for Consider the following CFLL1 = {an|n≥1}L2 = {bnan|n≥1}L3 = {0n1m |n = 2m, n,m ≥ 0}L4 = {ap|p is odd number}How many statements are true?(i) Complement of L1 is also regular.(ii) Union of L2 and L3 is also CFL(iii) Intersect of L1 and L4 is also CFL(iv) Concatenation of L1 and L2 is also CFLCorrect answer is '4'. Can you explain this answer? in English & in Hindi are available as part of our courses for Computer Science Engineering (CSE). Download more important topics, notes, lectures and mock test series for Computer Science Engineering (CSE) Exam by signing up for free.
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